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Is 0 a term of the A.P.:- 31,28,25,...? Justify your answer. |
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Answer» a=31 d=28-31=-3 t(n) = a + (n-1) d 0 = 31 + (n-1)(-3) -31 = - 3(n-1) 31/3 = n-1 n = (31+3)/3 n = 34/3 as n is fractional therefore 0 is not a term of the AP. |
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