1.

iron has a circular cross section of radius 1 mm and resistivity of its material is 2 into 10 raise to minus 6 find the length of whose resistance is 20 Ohm​

Answer»

EXPLANATION:

GIVEN radius =R = 1mm =

{10}^{ - 3} m

resisitivty =$ =

2 \times  {10}^{ - 6}

length =L = ? , resistance R= 20 OHM .

using formula R=$l/a

Area = a =

\pi {r}^{2}

therefore a =

3.14 \times  {10}^{ - 6} m {}^{2}

therefore ,

length = l = a × R / $

l = 31.4 meter ...



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