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iron has a bcc unit cell with edge length of 286.65 pm. The density of iron is 7.87g /cm³. Use this information to calculate the Avogadro’s number. (Fe=56u) |
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Answer» dge length = 286.65pm Density = 7.87gcm⁻³atomic mass = 56uTo find:Avogadro's number SOLUTION:Iron has bcc unit cell means, Z = 2 here, Z = number of atoms PER unit cell FORMULA used for density is - here, Z = no. of atoms per unit cell M = atomic mass a = edge length D = density Na = Avogadro's number So, by SUBSTITUTING the values we get, Therefore, avogadro's number is 6.022 × 10²³ mol⁻¹. |
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