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Ionisation energy of `He^(+) " is " 19.6 xx 10^(-18)J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^(2+)` isA. `4.41 xx 10 ^(-19) J "atom"^(-1)`B. `-4.41 xx 10 ^(-17) J "atom"^(-1)`C. `-2.2 xx 10 ^(-15) J "atom"^(-1)`D. `8.82 xx 10 ^(hatu17) J "atom"^(-1)` |
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Answer» Correct Answer - 2 I.P of `He^(+)= 19.6 xx 10^(-8)J//atom` `(E_(1))_(He^(+)) = - 19.6 xx 10^(-18)` `(E_(1))_(He^(+))/((E_(2))_(Li^(+2)))=((Z_(1)^(2)))/((Z_(2))_(Li^(+2))^(2)) xx ` `-(19.6xx10^(-18))/((E_(1))_(Li^(+2)))=((2)^(2))/((3)^(2))=((1)^(2))/((1)^(2))` `((n_(2))_(Li^(+2))^(2))/((n_(1))_(He^(+))^(2))` `(E_(1))_(Li^(+2)) = (9)/(4) xx (-19xx10^(-18))` `=- 4.41 xx 10^(-17)J//"atom"` |
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