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Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.A. `4.41xx10^(-16)J atom^(-1)`B. `-4.41xx10^(-17)J atom^(-1)`C. `-2.20xx10^(-15)J atom^(-1)`D. `8.82xx10^(-17)J atom^(-1)` |
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Answer» Correct Answer - B `E_(1)/E_(2)=Z_(1)^(2)/Z_(2)^(2)xxn_(2)^(2)/n_(1)^(2)` `((-19.6xx10^(-18)))/(E_(2))=2^(2)/3^(2)xx1^(2)/1^(2)` `E_(2)=-4.41xx10^(-17)J atom^(-1)` |
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