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Ionisation constant of `CH_(3)CO O H ` is `1.7xx10^(-5)` and concentration of `H^(+)` ions is `3.4 xx 10^(-4)`. Then initial concentration of `CH_(3) C O O H` molecules isA. `3.4xx10^(-4)`B. `3.4xx10^(-3)`C. `6.8xx10^(-3)`D. `1.7xx10^(-3)` |
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Answer» Correct Answer - C `{:(,XH_(3)CO OH" " hArr" " CH_(3)CO O^(-) + H^(+)),("Initial conc."," "a),("At. eqm.",(a-3.4 xx 10^(-4)) " "3.4xx10^(-4)" " 3.4 xx 10^(-4)):}` `((3.4xx10^(-4))(3.4xx10^(-4)))/((a-3.4 xx 10^(-4))) = 1.7 xx 10^(-5) ` (Given) or, `(a-3.4xx10^(4))=((3.4xx10^(-4))^(2))/(1.7xx10^(-5))=6.8xx10^(-3)` or `a=6.8xx10^(-3)+3.4xx10^(-4)~~ 6.8 xx 10^(-3)` |
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