Ione faraday of electricity will liberate one gram atom of a metal from a solution ofA. `AuCl_(3)`B. `CuSO_(4)`C. `BaCl_(2)`D. `KCl`

Ione faraday of electricity will liberate one gram atom of a metal fro

1.	Ione faraday of electricity will liberate one gram atom of a metal from a solution ofA. `AuCl_(3)`B. `CuSO_(4)`C. `BaCl_(2)`D. `KCl`
Answer» Correct Answer - D `KCl hArr K^(+) + Cl^(-)` and `K^(+) + e^(-) rarr K` Thus, one mole `KCl` need one mole electrons to liberate one gram metal atom. One mole electron charge is equal to `96500 C (1 F)`. Hence, `1 F` charge will liberate one gram atom of metal from solution of `KCl`,

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Ione faraday of electricity will liberate one gram atom of a metal from a solution ofA. `AuCl_(3)`B. `CuSO_(4)`C. `BaCl_(2)`D. `KCl`

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