. Iof (d+bhr廴2b(a +cir+ (b4d)=0 are real and equal then a, b, e are

1.	. Iof (d+bhr廴2b(a +cir+ (b4d)=0 are real and equal then a, b, e are in) A.P3. The equa2) Н.Р.3)G.Р.interval4) A.G.P1) (0, 2T
Answer» If the roots of the equation ( a2 + b2 ) x2 - 2 ( ac + bd ) x + ( c2 + d2 ) =0 are equal prove that a/ b = c/ d . here 2 denotes square ( a² + b²)x² -2( ab + cd)x +( c² + d²) = 0 roots are equal so, D = b² -4ac =0 {2(ab + cd)}² -4(a² +b²)(c² + d²) =0 4(ab+ cd)² -4(a² + b²)(c²+ d²) =0 ( a²b²+c²d² +2abcd ) -a²c²-a²d²-b²d² -b²c² =0 -a²c² -b²d² + 2abcd =0 -( a²c² + b²d² -2abcd) =0 {(ac-bd)²} =0 ac -bd =0 ac = bd a/b = d/c similar ques, might help! By this result how can we say that a, b, c are in ap or gp or hp or agp And u don't solve that question which I have posted

. Iof (d+bhr廴2b(a +cir+ (b4d)=0 are real and equal then a, b, e are in) A.P3. The equa2) Н.Р.3)G.Р.interval4) A.G.P1) (0, 2T

Answer»

If the roots of the equation ( a2 + b2 ) x2 - 2 ( ac + bd ) x + ( c2 + d2 ) =0 are equal prove that a/ b = c/ d . here 2 denotes square

( a² + b²)x² -2( ab + cd)x +( c² + d²) = 0

roots are equal so, D = b² -4ac =0

{2(ab + cd)}² -4(a² +b²)(c² + d²) =0

4(ab+ cd)² -4(a² + b²)(c²+ d²) =0

( a²b²+c²d² +2abcd ) -a²c²-a²d²-b²d² -b²c² =0

-a²c² -b²d² + 2abcd =0

-( a²c² + b²d² -2abcd) =0

{(ac-bd)²} =0

ac -bd =0

ac = bd

a/b = d/c

similar ques, might help!

By this result how can we say that a, b, c are in ap or gp or hp or agp

And u don't solve that question which I have posted