1.

Intregation of logx

Answer»

Integration of log x is x(logx - 1)

Explanation:

At first we can write log x as 1.log x

Then we will apply partial fraction to it. i.e. ∫u v dx = u∫v dx −∫u' (∫v dx) dx.
here, u = log x and v = 1
∫1.log x dx = logx∫1 dx - ∫d/dx(log x)∫(1dx) dx
xlog x - ∫1/x(x) dx 
xlog x - ∫1 dx
xlog x - x

so, x(logx - 1)



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