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Internal Energy (E,also denoted by U): Every system having some quantity of matter is associated with a definite amount of energy, called internal energy. `E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+`.... `DeltaE=E_("Final")-E_("initial")` `DeltaE=q_v`, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas. It is an extensive property & a state function.It is exclusively a function of temperature. If `DeltaT=0 , DeltaE=0` as well. The internal energy of a certain substance is given by the following equation : U=3 PV+84 where U is given in kJ/kg, P is in kPa, and V is in `m^3//kg` A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A `0.2 m^3` to a final pressure 100 kPa in a process in which pressure and volume are related by `PV^2`=constant. In another process the same system expands according to the same pressure-volume relationship as in above question, but from the same initial state of the final state as in above question, but the heat transfer in this case is +30 kJ.Then the work transfer for this process is :A. `-80 kJ`B. `-60 kJ`C. `-90 kJ`D. `-150 kJ` |
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Answer» Correct Answer - D Since the end states are the same, `DeltaU` would remain the same as in above problem. `W=DeltaU-q` `W= -120-30= -150 kJ` |
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