1.

Integration of (sin 2x √ 1- cos 4x) dx​

Answer»

Step-by-step explanation:

Let [math]\displaystyle I = \int \dfrac{\sin^2(X) + \COS^2(x)}{\sqrt{1 + \cos(4X)}} \, DX[/math] As, [ math]\sin^2(x) + ... =(1/√2)integ.dx/cos2x.



Discussion

No Comment Found

Related InterviewSolutions