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Integrating factor of differential equation `cosx(dy)/(dx)+ysinx=1`is(a)`( b ) (c)cosx (d)`(e)(b) `( f ) (g)tanx (h)`(i)(c)`( d ) (e)secx (f)`(g)(d) `( h ) (i)sinx (j)`(k)A. `cosx`B. `tanx`C. `secx`D. `sinx` |
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Answer» Correct Answer - C `cosx(dy)/(dx)+ysinx=1` or `(dy)/(dx)+y(sinx)/(cosx)=secx` `therefore intPdx=int(sinx)/(cosx)dx` `=-logcosx` `=log secx` `therefore` I.F. `=e^(intPdx)=e^(log secx)=secx` |
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