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Integrate [x+1/x]^3please solve it fast |
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Answer» Step-by-step explanation:I think you mean ∫[X+(1/x)]³ dx=∫f(x)dx ,for which you have no CHOICE but to expand the INTEGRAND in the smart way... ① f(x)=[x+(1/x)]³ =[(x²+1)/x]³ =(1+x²)³/x³ ={1+3x²+3x^4+x^6}/x³ =x^(-3)+3[x^(-1)]+3x+x³ ② ∫f(x)dx =-½(1/x²)+3㏑|x|+3(x²/2)+¼x^4+C |
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