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Integrate: ∫tan-1 x dx |
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Answer» ∫tan-1 x dx = ∫1.tan-1 x dx = tan-1 x∫1. dx - ∫1/(1 + x2)x dx = x tan-1 x - (1/2)∫2x/(1 + x2) dx = x tan-1 x - (1/2)log(1 + x2) + k |
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