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Integrate ∫sec x dx. |
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Answer» ∫ sec x dx ∫sec x(sec x + tan x)/(sec x + tan x) dx ∫(sec2 x + sec x tan x)/(sec x + tan x) dx Let, sec x + tan x = t (sec x + tan x + sec2 x) dx = dt ∫(dt/dt) = loget = loge(sec x + tan x) + c |
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