Saved Bookmarks
| 1. |
Integrate ∫(e2x - 1)/(e2x + x) dx |
|
Answer» Dividing numerator and denominator by ex, we get ∫(ex - e-x)/(ex + e-x)dx Now d/dx(ex + e-x) = ex - e-x = log(ex + e-x) +c |
|