1.

Integrate e^6y.y^2 dy​

Answer»

Step-by-step explanation:

M∂y = ∂2I∂y ∂X

∂N∂x = ∂2I∂y ∂x

they end up the same! And so this will be true:

∂M∂y = ∂N∂x

When it is true we have an an "exact equation" and we can proceed.

And to DISCOVER I(x, y) we do EITHER:

I(x, y) = ∫M(x, y) dx (with x as an independent VARIABLE), OR

I(x, y) = ∫N(x, y) dy (with y as an independent variable)

And then there is some extra work (we will show you) to arrive at the general solution I think it had helped you



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