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Integral tan²x × twn²x dx.solve it |
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Answer» Answer: You can start by WRITING tan 2 ( x ) = sin 2 ( x ) cos 2 ( x ) ∫ tan 2 ( x ) d x = ∫ sin 2 ( x ) cos 2 ( x ) d x =
using: sin 2 ( x ) = 1 − cos 2 ( x ) you get: = ∫ 1 − cos 2 ( x ) cos 2 ( x ) d x = ∫ [ 1 cos 2 ( x ) − 1 ] d x = = ∫ 1 cos 2 ( x ) d x − ∫ 1 d x =
= tan ( x ) − x + c
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