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`int1/(y(1-ay))`dy |
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Answer» `int1/(y(1-ay))dy` `Let 1/(y(1-ay))=A/y+B/(1-ay)` `1=A(1-ay)+By` `-aA+B=0` `A=1` `B=a` `intdy/(y(1-ay))=intdy/y+int(ady)/(1-ay)` `=lny+a(-1/a)ln(1-ay)` `=lny-ln(1-ay)` `=ln(y/(1-ay))+c`. |
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