Int x^n dx for n = - 1 is(A) Not defined(B) (x ^ (n + 1))/(n + 2) + c

1.	Int x^n dx for n = - 1 is(A) Not defined(B) (x ^ (n + 1))/(n + 2) + c (C) log x + c (D) 2 log x+c
Answer» The ANSWER to this question is STRAIGHT forward lnx+C Now the question comes that why this problem can't be solved by simple power addition ( $\LARGE \int {x}^{n} dx = \frac{ {x}^{n + <klux>1</klux>} }{n + 1}$ ) The answer is if we add 1 to -1 and put it in denominator The fraction will become undefined. Hence we SOLVE this by taking log. Final answer Option C

Int x^n dx for n = - 1 is(A) Not defined(B) (x ^ (n + 1))/(n + 2) + c (C) log x + c (D) 2 log x+c

Answer»

The ANSWER to this question is STRAIGHT forward lnx+C

Now the question comes that why this problem can't be solved by simple power addition ( $\LARGE \int {x}^{n} dx = \frac{ {x}^{n + <klux>1</klux>} }{n + 1}$ )

The answer is if we add 1 to -1 and put it in denominator The fraction will become undefined.

Hence we SOLVE this by taking log.

Final answer

Option C

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Int x^n dx for n = - 1 is(A) Not defined(B) (x ^ (n + 1))/(n + 2) + c (C) log x + c (D) 2 log x+c​

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Int x^n dx for n = - 1 is(A) Not defined(B) (x ^ (n + 1))/(n + 2) + c (C) log x + c (D) 2 log x+c