1.

\( \int \frac{1-\sin x}{\cos x} d x \) equals

Answer»

1-Sinx = sin²x/2 + cos²x/2 -2sinx/2cosx/2 = ( cosx/2 - sinx/2  )²

cosx = cos²x/2 - sin²x/2 = ( cosx/2 - sinx/2 )(cosx/2 + sinx/2 )

then put this values in given integration and substitute  t = cosx/2 + sinx/2  

it reduces in simple integration.




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