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`int (dx)/((4+16x^(2)))=?`A. `(1)/(32)tan^(-1)4x+C`B. `(1)/(16)tan^(-1)""(x)/(2)+C`C. `(1)/(8)tan^(-1)""2x+C`D. `(1)/(4)tan^(-1)""(x)/(2)+C` |
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Answer» Correct Answer - C `I=int (1)/(16).int (dx)/(((1)/(4)+x^(2)))=(1)/(16).(dx)/({((1)/(2))^(2)+x^(2)})=(1)/(16).(1)/(((1)/(2)))tan^(-1)""(x)/(((1)/(2)))+X=(1)/(8)tan^(-1)2x+c.` |
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