1.

Int dx/√2ax-x,^2 = a^n sin^-1[x/a-1] . The value of n is (a) 0 (b) —1 (c) 1 (d) none of these. You may use dimensional analysis to solve the problem.

Answer»

Int dx/√2ax-x,^2 = a^n sin^-1[x/a-1] .

The value of n is
(a) 0 (b) —1
(c) 1 (d) none of these.
You may use dimensional analysis to solve the problem.



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