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\[ \int_{0}^{41 \pi / 2} \sin x d x= \] (a) 1 (b) 2 (c) 3 (d) 4 |
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Answer» The correct option is (a) 1. \(\int\limits_0^{\frac{41\pi}2}sin\,x\,dx=-[cos\,x]_0^{\frac{41\pi}2}\) = \(-(cos\frac{41\pi}2-cos0)\) = -(0- 1) = 1 |
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