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Insert five numbers between 8 and 26 such that the resulting sequence is an A.P. |
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Answer» Let required five numbers be x1, x2, x3, x4, x5 ∴ 8, x1, x2, x3, x4, x5, 26 are in A.P. ⇒ First term = 8 and seventh term = 26 ⇒ a = 8 and a + 6d - 26 ⇒ 3 = 8 and 6d = 26 – a = 26 – 8 = 18 ⇒ a = 8 and d = 3 Hence x1= a + d = 8 + 3 = 11 x2 = a + 2d = 8 + 6 = 14 x3 = 17, x4 = 20, x5 = 23 |
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