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| 1. |
Insert 6 no. Between 3 & 24 such that the resulting sequence is an AP |
| Answer» As 6 terms to be inserted between 3 and 24 resulting AP would be\xa0\xa03, a2, a3, a4, a5, a6,a7, 24First term a =3 , a8 = 24a+7d= 243+7d =24d=3a2=a+d=3+3=6a3=a+2d=3+6=9a4=12a5=15a6= 18a7=21so 6 terms are 6,9,12,15,18,21 | |