Insert 4 rational no. between 5/6 and 7/12

1.	Insert 4 rational no. between 5/6 and 7/12
Answer» Solution: First RATIONAL no $\frac{1}{2} \times ( \frac{5}{6} + \frac{7}{12} ) \\$ $= > \: \frac{1}{2} \times \frac{10 + 7}{12} \\$ [ *LCM of both the no is 12] $= > \: \frac{1}{2} \times \frac{17}{12 } \\$ $= > \frac{17}{<klux>24</klux>} \\$ Second rational no $\frac{1}{2} \times ( \frac{5}{6} + \frac{17}{24} ) \\$ $= > \: \frac{1}{2} \times \frac{20 + 17}{24} \\$ . [ lcm of both the no is 24] $= > \: \frac{1}{2} \times \frac{37}{24 } \\$ $= > \frac{27}{48} \\$ THIRD rational no $\frac{1}{2} \times ( \frac{17}{24} + \frac{7}{12} ) \\$ $= > \: \frac{1}{2} \times \frac{17 + 14}{24} \\$ . [ lcm of both the no is 24] $= > \: \frac{1}{2} \times \frac{31}{24} \\$ $= > \frac{31}{48} \\$ Forth rational no $\frac{1}{2} \times ( \frac{17}{24} + \frac{37}{48} ) \\$ $= > \: \frac{1}{2} \times \frac{34 + 37}{48} \\$ . [ lcm of both the no is 48*] $= > \: \frac{1}{2} \times \frac{71}{48 } \\$ $= > \frac{71}{96} \\$

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