Inner circumference of a circular path is 440 m. Width of the path is

1.	Inner circumference of a circular path is 440 m. Width of the path is 14 m. Finddiameter of the outer circle of the circular path.
Answer» ★GIVEN : Circumference of PATH = 440 cm Width = 14 ★TO FIND : OUTER diameter? ★SOLUTION : FIRSTLY let's find the radius $\sf \: 440 = 2 \dfrac{22}{7}$ $\sf \: 440 = 2 \times \dfrac{22}{7}$ $\sf \: 440 = \dfrac{44}{7}$ $\sf \: r = \cancel{ 440 \times \dfrac{7}{44}}$ $\sf \: r = 10 \times 7r=10×7$ Hence :- Radius = 70 m $\sf \: Outer \: diameter = 2(70 + 14)$ $\sf \: Outer \: diameter = 168 \:$ Hence :- Outer diameter = 168 m. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELPS\:UH :)}}}}}}$ $\red{\tt{sωєєтcнαям♡~}}$