Initially a car is moving with speed of 20 ms- and covers a distance of 100 m before it comes to rest.On making the initial speed of car 40 ms-keeping the acceleration same, the distancetravelled by car before it comes to rest is

Initially a car is moving with speed of 20 ms- and covers a distance

1.	Initially a car is moving with speed of 20 ms- and covers a distance of 100 m before it comes to rest.On making the initial speed of car 40 ms-keeping the acceleration same, the distancetravelled by car before it comes to rest is
Answer» 800M Explanation:0²=20²+2aSa=-400/2Sa=-400/200a=-2m/s²Acceleration is same, now u=40m/s0²=40²+2aS¹ S¹=-1600÷(2×-2)S¹=800m

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Initially a car is moving with speed of 20 ms- and covers a distance of 100 m before it comes to rest.On making the initial speed of car 40 ms-keeping the acceleration same, the distancetravelled by car before it comes to rest is​

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Initially a car is moving with speed of 20 ms- and covers a distance of 100 m before it comes to rest.On making the initial speed of car 40 ms-keeping the acceleration same, the distancetravelled by car before it comes to rest is