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Initial volume of a gas is `1 L` at temperature `100 K`. What is the volume of a gas at `300 K`.A. `1`B. `2`C. `3`D. `4` |
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Answer» Given `V_(1)=1 L`, `T_(1)=100 K`, `T_(2)=300 K`, `V_(2)=?` We know, `(V_(1))/(T_(1))=(V_(2))/(T_(2)) implies V_(2)=(V_(1)T_(2))/(T_(1))` `:. V_(2)=(1xx300)/(100)=3` |
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