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INDEFINITE INTC04x1 |
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Answer» I=∫(1+cos4x)/(cotx-tanx) dx I= ∫(1+ cos4x)sinx cosx/(cos²x-sin²x) dx = ∫(1+ 2cos²2x-1)sin2x/2cos2x dx I= ∫cos2x sin2xdx = 1/2∫ sin4xdx = 1/8 [-cos4x] +c |
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