1.

INDEFINITE INTC04x1

Answer»

I=∫(1+cos4x)/(cotx-tanx) dx

I= ∫(1+ cos4x)sinx cosx/(cos²x-sin²x) dx

= ∫(1+ 2cos²2x-1)sin2x/2cos2x dx

I= ∫cos2x sin2xdx

= 1/2∫ sin4xdx

= 1/8 [-cos4x] +c



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