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ind the15 5ly solve for x and y:10y +x2y+4;15y-5=-2; |
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Answer» 10/x+y +2/x-y=4________(1)15/x+y-5/x-y=-2________(2)let 1/x+y=A and 1/x-y=Buatherefore eqn 1 and 2 will become 10A+2B=415A-5B=-2 Now multiplying eqn 1 by -5 and eqn 2 by 2 we get -50A-10B=-2030A-10B=-4Now by elimination method we have A=16/80=1/5and B=1but 1/x+y=A and 1/x-y =Bputting the values of A and B we get x+y=5____(3) and x-y=1______(4)Now from eqn 3 we get x=5-y Now putting the value of x in eqn 4 we get y=2 and x=5-y i.e x=5-2=3. Therefore x=3 and y=2 |
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