Saved Bookmarks
| 1. |
In Young's double-slit experiment using monochromatic light of wavelength lambda, the intensity of light at a point on the screen where path difference is lambda, is K units. What is the intensity of light at a point where path difference is lambda//3? |
|
Answer» Solution :In YDSE (Young.s Double Slit Experiment), intensity of light at a given point on the screen is, `I=I_(0)COS^(2){(k(r_(2)-r_(1)))/(2)}` For first point, `r_(2)-r_(1)=LAMDA` I=K and so, `K=I_(0)cos^(2){(1)/(2)xx(2pi)/(lamda)xxlamda}` `:.K=I_(0)(1)` `:.I_(0)=K""....(1)` For second point, `(r_(2)-r_(1))=(lamda)/(3)` and so, `I.=I_(0)cos^(2){(k(r_(2)-r_(1)))/(2)}` `:.I.=Kcos^(2){(1)/(2)xx(2pi)/(lamda)xx(lamda)/(3)}` `:.I.=Kcos^(2)((pi)/(3))=K((1)/(2))^(2)` `:.I.=(K)/(4)` |
|