In Young's double slit experiment the light emitted from source has lambda = 6.5 xx 10^(-7) m and the distance between the two slits is 1 mm. Distance between the screen and slit is 1 metre. Distance between the screen and slit is 1 metre. Distance between third dark and fifth bright fringes will be :

In Young's double slit experiment the light emitted from source has la

1.	In Young's double slit experiment the light emitted from source has lambda = 6.5 xx 10^(-7) m and the distance between the two slits is 1 mm. Distance between the screen and slit is 1 metre. Distance between the screen and slit is 1 metre. Distance between third dark and fifth bright fringes will be :
Answer» `3.2` mm `1.63` mm `0.585` mm `2.31` mm Solution :`x_(5) = (n LAMBDA D)/(d) = 32.5 xx 10^(-4) m` `x_(3) = (2n - 1) (lambda)/(2) (D)/(d) = 16.25 xx 10^(-4) m` `x_(5) - x_(3) = 1.63 mm`.

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