1.

In YDSE, the thickness of a glass slab (μ=1.5) which should be placed in front of the upper slit S1 so that the central maximum now lies at a point where the 5th bright fringe was lying earlier (before inserting the slab), is given by x×104 ˙A. The value of x is (Integer only)[Wavelength of light =5000 ˙A]

Answer» In YDSE, the thickness of a glass slab (μ=1.5) which should be placed in front of the upper slit S1 so that the central maximum now lies at a point where the 5th bright fringe was lying earlier (before inserting the slab), is given by x×104 ˙A. The value of x is (Integer only)

[Wavelength of light =5000 ˙A]


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