1.

In which value of K,x=2/3 is a solution of equation Kx^2-x-2=0.please solve in full step.

Answer»

Hey USER here is your answer....

x=2/3

---> Given EQUATION- kx^2-x-2

◆ K(2/3)^2-(2/3)-2=0

◆k(4/9)-(2/3)-2=0
◆4k/9-2/3-2

◆Take L.C.M

4K-6-18/9=0

◆4K-24=0
◆4K=24
◆K=24/4

◆K=6


HOPE it helps you☺️



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