1.

In two concentric circles prove that all chords of the outer circle which touch the inner circle are of equal length.

Answer» `In/_AOC`
`OC^2+AC^2=OA^2`
`r_1^2+AC^2=r_2^2`
`AC=sqrt(r_2^2-r_1^2)`
`AB=2sqrt(r_2^2-r_1^2)`
AC=BC
AB`_|_`BC
C is mid point of AB
length of chord is constant =`2sqrt(r_2^2-r_1^2)`.


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