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In two concentric circles prove that all chords of the outer circle which touch the inner circle are of equal length. |
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Answer» `In/_AOC` `OC^2+AC^2=OA^2` `r_1^2+AC^2=r_2^2` `AC=sqrt(r_2^2-r_1^2)` `AB=2sqrt(r_2^2-r_1^2)` AC=BC AB`_|_`BC C is mid point of AB length of chord is constant =`2sqrt(r_2^2-r_1^2)`. |
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