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In `triangleABC, (a-b)/(a+b)=`A. `cot((A-B)/(2))cot((A+B)/(2))`B. `tan((A-B)/(2))cot((A+B)/(2))`C. `cot((A-B)/(2))tan((A+B)/(2))`D. `tan((A-B)/(2))tan((A+B)/(2))` |
| Answer» Correct Answer - B | |