In triangle, show that sin square A/2+sin square (B+C/2)=1 – InterviewSolution

1.	In triangle, show that sin square A/2+sin square (B+C/2)=1
Answer» sinA/2 * sinA/2 + sin(B+C)/2 * sin(B+C)/2 = sinA/2 * sinA/2 + sin(pie-A)/2 * sin(pie-A)/2 = sinA/2 * sinA/2 + cosA/2 * cosA/2 = 1

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