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In triangle pqr angle P is equals to 90 degree PR + QR is equal to 25 cm and PQ is equal to 7 cm determine the values of sin R cos R tan Ranswer is urgent and right answer please |
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Answer» <P>First you have to solve for QR and PR. PR+QR = 25 (given) and PR=25-QR 52 + QR2= PR2 (pythagorean theorem) Then substitute PR to get this equation = 52 + QR2 = (25-QR)2 Solve for QR 52 + QR2 = 625 - 50QR +QR2 .........(QR2 cancels out) 52 = 625 - 50 QR -600 = -50 QR QR= 12 Solve for PR using original equation. PR= 13 Now DRAW the triangle on your paper for help solving the next step... Sin = opposite/ hypotenuse Sin(P)= 12/13 Cos= Adjacent/ hypotenuse Cos(P) = 5/13 Tan= opposite/ adjacent Tan(P) = 12/5
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