In triangle ABC tan(A-B+C)=?

1.	In triangle ABC tan(A-B+C)=?
Answer» Step-by-step EXPLANATION: A+B+C=180 so that B+C=180-A A-B-C=A-(B+C)=A-(180-A)=2A-180 TAN(x-y)=(tanx-tany)/(1+tanxtany) tan(2A-180)=(tan2A-tan(180))/(1_+tan2Atan(180))=tan2A/1-tan2A) SINCE tan(180)=-1

Answer»

Step-by-step EXPLANATION:

A+B+C=180 so that

B+C=180-A

A-B-C=A-(B+C)=A-(180-A)=2A-180

TAN(x-y)=(tanx-tany)/(1+tanxtany)

tan(2A-180)=(tan2A-tan(180))/(1_+tan2Atan(180))=tan2A/1-tan2A) SINCE tan(180)=-1

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In triangle ABC tan(A-B+C)=?​

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In triangle ABC tan(A-B+C)=?