In triangle ABC right angled at B . AB=5cm and angle ACB =30` determin

1.	In triangle ABC right angled at B . AB=5cm and angle ACB =30` determinethe lengths of the sides BC and AC.
Answer» ANSWER: BC = 5√3cm AC = 10cm Given: ∠ABC = 90° ∠ACB = 30° AB = 5cm To FIND: BC and AC Solution: FINDING AC $\sf sin30 ^\circ = \dfrac{AB}{AC}$ $\sf \dfrac{1}{2} = \dfrac{5}{AC}$ AC = 10cm Finding BC $\sf cos30^ \circ = \dfrac{BC}{AC}$ $\sf\dfrac{\sqrt{3}}{2} = \dfrac{BC}{10}$ 2BC = 10√3 $\sf BC = \dfrac{10\sqrt{3}}{2}$ BC = 5√3