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In triangle abc prove that cos a + b + cos c is equal to zero |
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Answer» Answer: PLEASE MARK ME AS BRAINLIEST ANSWER AND FOLLOW ME. Step-by-step explanation: By ANGLE sum property of TRIANGLES, 180 deg So, (A + B) = 180 - C ==> cos(A + B) = cos(180 - C) = -cos(C) So, cos(A + B) + cos(C) = 0 [PROVED] |
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