1.

In triangle ABC, LC=90tanA= 1/3findSin A CosB + Cos A SinB

Answer»

Step-by-step EXPLANATION:

Step-by-step explanation:

tanA=BC/AB=‌1/root 3

Thus BC=1 AB=root 3

In TRIANGLE ABC,

AB2+BC2=AC2

Thus AC=2(BY PYTHAGORAS THEORM)

SinAcosC+cosAsinC=1/2*1/2+root3 /2*root3/2

=1/4+3/4

=4/4

=1



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