1.

In triangle ABC , AB =AC , anlgle BAC =50°,now CB is extended to D , then the external angle at angle DAB isa) 90° b) 70°c) 115°d) 80°​

Answer»

ANSWER:

(c)115°

Step-by-step explanation:

As AB=AC

angle ABC=angle ACB (angles opposite to equal sides are equal)

angle BAC=50°(GIVEN)

angle ABC + angle BAC + angle ACB=180°(ASP)

2angleABC+50°=180°

2angleABC=130°

angle ABC=130°/2

angle ABC=65°

Similarly, angle ACB=65°

angle ABC+angle DAB=180°(exterior angle property)

angle DAB =180-65

angle DAB = 115°

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