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In triangle ABC, AB = 8cm, BC = 6cm , AC = 10cm. 1. What kind of triangle is this?2. What is the position of B based on the circle with AC as the diameter? Why?3. What is the position of A based on the circle with BC as the diameter? Why?4. What is the position of the point C based on the circle with diameter AB? |
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Answer» In Δ ABC AB2 + BC2 = 82 + 62 = 64 + 36 = 100 = AC2 Δ ABC is a right angled triangle. If we draw a circle taken in a AC as diameter, ∠B = 90°, Therefore the point B on the circle. Δ ABC is a right-angled triangle. If we draw a circle taking BC as diameter, ∠A < 90°, Therefore the position of point A will be outside the circle. If we draw a circle taking AB as diameter, ∠C < 90°, Therefore the position of point C will be outside the circle. |
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