In triangle ABC, AB = 6 cm, BC = 8 cm and AC = 10 cm from B perpendicu

1.	In triangle ABC, AB = 6 cm, BC = 8 cm and AC = 10 cm from B perpendicular is drawn on AC to cut at D then find area of triangle ADP+ triangle BPC
Answer» ong>Step-by-step explanation: so area of our TRIANGLE is 24units ok let X be the point on AB and let Y be the point on BC let we call length of BX as m and length of XY as n so now as i have claimed that angle C should be RIGHT angle so we have tanB=ACBC=nm 68=nm n=m68 n=m34 also area of triangle BXY = 12mn 24/2= 12mn so nm = 24 m34∗m=24 // as n=m34 m2=24∗43 m2=32 m=42–√ so BX is 42–√ // i hope i am not wrong but i hope method is clear

In triangle ABC, AB = 6 cm, BC = 8 cm and AC = 10 cm from B perpendicular is drawn on AC to cut at D then find area of triangle ADP+ triangle BPC

Answer»

ong>Step-by-step explanation:

so area of our TRIANGLE is 24units

ok let X be the point on AB and let Y be the point on BC

let we call length of BX as m and length of XY as n

so now as i have claimed that angle C should be RIGHT angle

so we have

tanB=ACBC=nm

68=nm

n=m68

n=m34

also area of triangle BXY = 12mn

24/2= 12mn

so nm = 24

m34∗m=24 // as n=m34

m2=24∗43

m2=32

m=42–√

so BX is 42–√

// i hope i am not wrong but i hope method is clear