In this question In a triangle ABC , AB>AC , AD is perpendicular to BC , prove that AB 2 - AC2 = BD 2= CD2 I have done it like this In triangle ABD AD2. = AB2 -. BD2. EQUATION 1 In triangle ADC AD2 =. AC2 - CD2. EQUATION 2 on combining. EQUATION 1 and 2 AD2 = AB2. -. BD 2 AD2 = AC2 - CD2. AB2 -. AC2 =. BD2 - CD2 hence proved IS THIS CORRECT

In this question In a triangle ABC , AB>AC , AD is perpendicular to

1.	In this question In a triangle ABC , AB>AC , AD is perpendicular to BC , prove that AB 2 - AC2 = BD 2= CD2 I have done it like this In triangle ABD AD2. = AB2 -. BD2. EQUATION 1 In triangle ADC AD2 =. AC2 - CD2. EQUATION 2 on combining. EQUATION 1 and 2 AD2 = AB2. -. BD 2 AD2 = AC2 - CD2. AB2 -. AC2 =. BD2 - CD2 hence proved IS THIS CORRECT
Answer» In this question In a triangle ABC , AB>AC , AD is perpendicular to BC , prove that AB 2 - AC^{2 _{= BD 2= CD2} _{I have done it like this In triangle ABD AD2. = AB2 -. BD2. EQUATION 1 In triangle ADC AD2 =. AC2 - CD2. EQUATION 2 on combining. EQUATION 1 and 2 AD2 = AB2. -. BD 2 AD2 = AC2 - CD2. AB2 -. AC2 =. BD2 - CD2 hence proved IS THIS CORRECT}}