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In thermodynamics the P-V work done is given byw = \(-\int dVP_{ext}\)For a system undergoing a particular process, the work done is ,w = \(-\int dV\big(\frac{RT}{V-b}- \frac{a}{V^2}\big)\)This equation is applicable to a (A) System that satisfies the van der Waals equation of state. (B) Process that is reversible and isothermal. (C) Process that is reversible and adiabatic. (D)Process that is irreversible and at constant isothermal. |
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Answer» Answer: (A, B, C) For 1 mole Vander Waal's gas \(P =\frac{RT}{V-b}- \frac{a}{V^2}\) If Pext = P, means process is reversible. For Vanderwaal gas, expression is correct for all reversible process. |
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