In thermal steady state of rod, temperature gradient is 5^(@) C/cm and temperature of its hot end is 100^(@)C, then at. . . . . . cm distance from hot end its temperature becomes 60^(@)C.

In thermal steady state of rod, temperature gradient is 5^(@) C/cm and

1.	In thermal steady state of rod, temperature gradient is 5^(@) C/cm and temperature of its hot end is 100^(@)C, then at. . . . . . cm distance from hot end its temperature becomes 60^(@)C.
Answer» SOLUTION :`L=(T)/(dT//dx)=(40)/(5)=8CM`